Hi!

> From: Matteo Croce <mcroce@microsoft.com>
> 
> Write a C version of memcpy() which uses the biggest data size allowed,
> without generating unaligned accesses.
> 
> The procedure is made of three steps:
> First copy data one byte at time until the destination buffer is aligned
> to a long boundary.
> Then copy the data one long at time shifting the current and the next u8
> to compose a long at every cycle.
> Finally, copy the remainder one byte at time.
> 
> On a BeagleV, the TCP RX throughput increased by 45%:
> 
> before:
> 
> $ iperf3 -c beaglev
> Connecting to host beaglev, port 5201
> [  5] local 192.168.85.6 port 44840 connected to 192.168.85.48 port 5201
> [ ID] Interval           Transfer     Bitrate         Retr  Cwnd
> [  5]   0.00-1.00   sec  76.4 MBytes   641 Mbits/sec   27    624 KBytes
> [  5]   1.00-2.00   sec  72.5 MBytes   608 Mbits/sec    0    708 KBytes
> 
> after:
> 
> $ iperf3 -c beaglev
> Connecting to host beaglev, port 5201
> [  5] local 192.168.85.6 port 44864 connected to 192.168.85.48 port 5201
> [ ID] Interval           Transfer     Bitrate         Retr  Cwnd
> [  5]   0.00-1.00   sec   109 MBytes   912 Mbits/sec   48    559 KBytes
> [  5]   1.00-2.00   sec   108 MBytes   902 Mbits/sec    0    690
> KBytes

That's really quite cool. Could you see if it is your "optimized
unaligned" copy doing the difference?>

+/* convenience union to avoid cast between different pointer types */
> +union types {
> +	u8 *as_u8;
> +	unsigned long *as_ulong;
> +	uintptr_t as_uptr;
> +};
> +
> +union const_types {
> +	const u8 *as_u8;
> +	unsigned long *as_ulong;
> +	uintptr_t as_uptr;
> +};

Missing consts here?

Plus... this is really "interesting" coding style. I'd just use casts
in kernel.

Regards,						Pavel

-- 
http://www.livejournal.com/~pavelmachek