Re: RFC: SysRq nice-all-RT-tasks is broken

[Steven Rostedt <rostedt@goodmis.org>]

[
  Added Peter

   Update: Laurent noticed that sysrq 'n' (nice-all-RT-tasks) calls
   __sched_setscheduler() form interrupt context. At the start of that
   function, there's a BUG_ON(in_interrupt()). The reason for that was
   due to the rt mutex pi code calling wait_lock. Which was not irq
   safe. Now it is, but that's not good enough.
]

On Wed, 8 Mar 2017 18:03:55 +0100
Laurent Dufour <ldufour@linux.vnet.ibm.com> wrote:

> On 08/03/2017 17:57, Steven Rostedt wrote:
> > On Wed, 8 Mar 2017 11:51:14 -0500
> > Steven Rostedt <rostedt@goodmis.org> wrote:
> > 
> >   
> >> Hmm, that commit was added in 2.6.18, and you're right, a lot has
> >> changed since then. Have you tried removing it and running it under
> >> lockdep, and see if it triggers any warnings?  
> > 
> > I did a little digging, and it appears that its the rt mutex wait lock
> > that the comment was referring to. Today that spin lock is irq safe. I
> > believe its safe to remove the BUG_ON(). Want me to send a patch?  
> 
> Sure, go ahead ;)
>

Actually, it's still not safe :-/

I just noticed this in the call path:

	raw_spin_unlock_irq(&task->pi_lock);

As well as other raw_spin_unlock_irq()s.

Which would enable interrupts regardless of the previous state.

One solution is to change all those to irqsave() but that seems to be a
big step for something that is rarely done (how many years has it been
since 2.6.18?).

I wonder if we should just have a special flag sent by that sysrq
trigger. Since it is causing all tasks to go "nice" there's no need to
do the pi chain walk in __sched_setscheduler().

-- Steve