Re: [PATCH v4] checkpatch: get default codespell dictionary path from package location

["Péter Ujfalusi" <peter.ujfalusi@linux.intel.com>]

On 11/10/2021 19:50, Joe Perches wrote:
> On Mon, 2021-10-11 at 14:49 +0300, Peter Ujfalusi wrote:
>> The standard location of dictionary.txt is under codespell's package, on
>> my machine atm (codespell 2.1, Artix Linux):
>> /usr/lib/python3.9/site-packages/codespell_lib/data/dictionary.txt
>>
>> Since we enable the codespell by default for SOF I have constant:
>> No codespell typos will be found - \
>> file '/usr/share/codespell/dictionary.txt': No such file or directory
> []
>> diff --git a/scripts/checkpatch.pl b/scripts/checkpatch.pl
> []
>> +	# Try to find the codespell install location to use it as default path
>> +	if (($codespell || $help) && which("codespell") ne "" && which("python") ne "") {
>> +		my $codespell_dict = `python -c "import os.path as op; import codespell_lib; print(op.join(op.dirname(codespell_lib.__file__), 'data', 'dictionary.txt'), end='')" 2> /dev/null`;
>> +		$codespellfile = $codespell_dict if (-e $codespell_dict);
>> +	}
> 
> This is really hard to read.
> 
> Can this be written something like
> 
> my $python_codespell_dict = << "EOF"
> import os.path as op
> import codespell_lib
> codespell_dir = op.dirname(codespell_lib.__file__)
> codespell_file = op.join(codespell_dir, 'data', 'dictionary.txt')
> print(codespell_file)
> EOF
> ;
> my $codespell_dict = `python3 -c "$python_codespell_dict" 2> /dev/null`;

Yes, this definitely looks much better, thanks for the suggestion!

-- 
Péter