From mboxrd@z Thu Jan 1 00:00:00 1970 From: Pasi =?iso-8859-1?Q?K=E4rkk=E4inen?= Subject: Re: Linux 3.4 dom0 kernel error loading xen-acpi-processor: Input/output error Date: Thu, 21 Feb 2013 14:42:52 +0200 Message-ID: <20130221124252.GR8912@reaktio.net> References: <20130221092434.GQ8912@reaktio.net> <20130221122913.GC6647@phenom.dumpdata.com> Mime-Version: 1.0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable Return-path: Content-Disposition: inline In-Reply-To: <20130221122913.GC6647@phenom.dumpdata.com> List-Unsubscribe: , List-Post: List-Help: List-Subscribe: , Sender: xen-devel-bounces@lists.xen.org Errors-To: xen-devel-bounces@lists.xen.org To: Konrad Rzeszutek Wilk Cc: David Vrabel , xen-devel@lists.xen.org List-Id: xen-devel@lists.xenproject.org On Thu, Feb 21, 2013 at 07:29:13AM -0500, Konrad Rzeszutek Wilk wrote: > On Thu, Feb 21, 2013 at 11:24:34AM +0200, Pasi K=E4rkk=E4inen wrote: > > Hello, > > = > > Does anyone know why loading xen-acpi-processor driver fails like this?: > > = > > # modprobe xen-acpi-processor > > FATAL: Error inserting xen_acpi_processor (/lib/modules/3.4.32-6.el6.ce= ntos.alt.x86_64/kernel/drivers/xen/xen-acpi-processor.ko): Input/output err= or > > = > > Using "modprobe -v" doesn't provide any more information about the prob= lem. > > Also there's nothing in dom0 kernel dmesg. > > = > > Hardware is Dell R510 server with Intel Xeon 5600 series CPU. = > > Xen 4.2.1. > > = > > Kernel is based on 3.4.32 (so the upstream kernel.org longterm stable v= ersion) = > > with some additional Xen patches backported from later upstream kernels= . = > > Any tips how to troubleshoot this? = > = > Rebuild the module and add this > diff --git a/drivers/xen/xen-acpi-processor.c b/drivers/xen/xen-acpi-proc= essor.c > index 316df65..5d824a2 100644 > --- a/drivers/xen/xen-acpi-processor.c > +++ b/drivers/xen/xen-acpi-processor.c > @@ -16,6 +16,7 @@ > * more details. > * > */ > +#define DEBUG 1 > = > #include > #include > = > = > That should help in figuring it out. > = Ok, I'll do that. Thanks! -- Pasi