On Wed, Feb 12, 2014 at 12:26:14PM +0100, Sebastian Hesselbarth wrote:
> You can cook it down to:
> 
> 	m = matches;
> 	/* Check against matches without compatible string */
> 	while (m->name[0] || m->type[0] || m->compatible[0]) {
> 		if (!m->compatible[0] && of_match_type_or_name(node, m)
> 			return m;
> 		m++;
> 	}

Will do.

Thanks,
Kevin