From mboxrd@z Thu Jan 1 00:00:00 1970 From: Cyril Hrubis Date: Fri, 7 Apr 2017 11:19:45 +0200 Subject: [LTP] [RFC] [PATCH v2] lib32: Add support for linking 32bit programs on 64bit In-Reply-To: <20170407105832.6f9d811a@linux-v3j5> References: <20170406124641.30179-1-chrubis@suse.cz> <20170407105832.6f9d811a@linux-v3j5> Message-ID: <20170407091945.GA536@rei.lan> List-Id: MIME-Version: 1.0 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: 7bit To: ltp@lists.linux.it Hi! > > +ifeq ($(filter -m32,$(CFLAGS)),) > > +$(MAKE_TARGETS): LDFLAGS += -L$(top_builddir)/lib$(subst -m,,$(filter -m32,$(CFLAGS))) > > +else > > +LDFLAGS += -L$(top_builddir)/lib > > +endif > > I think this breaks the build if you do 'make CFLAGS+=-m32' or './configure > CFLAGS=-m32' to build everything in compatability mode. Am I doing it wrong or > is this an issue? If -m32 is in CFLAGS the $(filter -m32,$(CFLAGS)) is nonempty and we will add -L$(top_builddir)/lib regardless. We will build the lib32 as well but never use it. And you have to pass LDLAGS=-m32 to the configure script as well, since the implicit rule to build an executable from list of object files is: $(CC) $(LDFLAGS) n.o $(LOADLIBES) $(LDLIBS) Hence if you pass -m32 only to CFLAGS the compiler will fail to link the ltp-pan binary. Passing -m32 in CFLAGS only works for testcases though, since they are compiled and linked in one try and hence use both LDFLAGS and CFLAGS. > > +# > > +# You should have received a copy of the GNU General Public License along > > +# with this program; if not, write to the Free Software Foundation, Inc., > > +# 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA. > > +# > > Minor nit: should be e-mail. Ok. I guess that we should use recent enough headers... -- Cyril Hrubis chrubis@suse.cz