i.MX6 - LDO Bypass anatop regulator in Linux 3.10.17_1.0.0-GA release

[ansaris <ansaris@iwavesystems.com>]

[-- Attachment #1: Type: text/plain, Size: 1740 bytes --]

Dear sir/madam,

We are using imx6Q sabresd platform for our development with Linux
3.10.17_1.0.0-GA BSP.

http://git.freescale.com/git/cgit.cgi/imx/linux-2.6-imx.git/commit/?h=imx_3.0.35_4.1.0&id=868d21a7fce9dc90808837e06b0d5e71e38b3b1b
In above link shows that, the anatop "reg_pu" value is set to 0x1F which 
is linux-3.0.35 kernel.

    @@ -81,6 +101,21 @@ void mx6_cpu_regulator_init(void)
    regulator_set_voltage(cpu_regulator,
    cpu_op_tbl[0].cpu_voltage,
    cpu_op_tbl[0].cpu_voltage);
    + if (enable_ldo_mode == LDO_MODE_BYPASSED) {
    + /*digital bypass VDDPU/VDDSOC/VDDARM*/
    + reg = __raw_readl(ANADIG_REG_CORE);
    + reg &= ~BM_ANADIG_REG_CORE_REG0_TRG;
    + reg |= BF_ANADIG_REG_CORE_REG0_TRG(0x1f);
    + reg &= ~BM_ANADIG_REG_CORE_REG1_TRG;
    + reg |= BF_ANADIG_REG_CORE_REG1_TRG(0x1f);
    + reg &= ~BM_ANADIG_REG_CORE_REG2_TRG;
    + reg |= BF_ANADIG_REG_CORE_REG2_TRG(0x1f);
    + __raw_writel(reg, ANADIG_REG_CORE);
    + /* Mask the ANATOP brown out interrupt in the GPC. */
    + reg = __raw_readl(gpc_base + 0x14);
    + reg |= 0x80000000;
    + __raw_writel(reg, gpc_base + 0x14);
    + }
    clk_set_rate(cpu_clk, cpu_op_tbl[0].cpu_rate);

But with reference of Linux 3.10.17_1.0.0-GA BSP, During the LDO bypass 
the "reg_pu" value is not set to 0x1F as mentioned below. Please clarify.
file:u-boot-imx/arch/arm/cpu/armv7/mx6/soc.c
void set_anatop_bypass(void)
{
struct anatop_regs *anatop = (struct anatop_regs *)ANATOP_BASE_ADDR;
u32 reg = readl(&anatop->reg_core);
/* bypass VDDARM/VDDSOC */
reg = reg | (0x1F << 18) | 0x1F;<-- PMU_REG_CORE's reg_arm & reg_soc 
values are set to 0x1F
writel(reg, &anatop->reg_core);
}



Thank you,
Regards,
Ansari

[-- Attachment #2: Type: text/html, Size: 4629 bytes --]