Re: Ques on FIO output (how to interpret iops)

[John Cagle <jcagle@gmail.com>]

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On Sat, Jun 20, 2009 at 1:27 AM, Jens Axboe <jens.axboe@oracle.com> wrote:

> On Fri, Jun 19 2009, Learner Study wrote:
> > Hi:
> >
> > How do I calculate total IOPS done by different FIO threads/jobs?
> >
> > Following is output from FIO (with two threads)...
> >
> > Each thread shows "bw" and "iops" numbers. Towards the end of output log,
> > there is "aggrb" which is sum of individual "bw" of threads, but "io"
> field
> > (3 line from the bottom of output below) doesn't seem to be sum of
> > individual thread iops....
> >
> > For example, Thread_1 has bw: 15k iops: 29366
> > Thread_2 has bw: 15k iops: 29445
> > But, the summary towards the end (third line from bottom of output), says
> > "io=1,723MiB, aggrb=30,105KiB/s".
> >
> > In this aggrb is good but io doesn't match up (it should be 58781) ! Can
> > someone please educate what am I missing?
>
> Can you try a newer version? If the problem is still there, the best way
> to get it fixed is to send my a simple job file that reproduces the
> problem, and then I can easily fix it for you.
>

I thought the "io=" summary at the end was the total amount of I/O performed
(in megabytes), not the total number of IOPS.

What were your block size and length of run for the example?

John

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