On Fri, 2022-02-18 at 10:08 -0600, Eric W. Biederman wrote: > > Maybe I am reading the lifetimes wrong but is there > any chance the code can just do something like the diff below? > > AKA have a special version of kern_umount that does the call_rcu? > > Looking at rcu_reclaim_tiny I think this use of mnt_rcu is valid. > AKA reusing the rcu_head in the rcu callback. > > > diff --git a/fs/namespace.c b/fs/namespace.c > index 40b994a29e90..7d7aaef1592e 100644 > --- a/fs/namespace.c > +++ b/fs/namespace.c > @@ -4395,6 +4395,22 @@ void kern_unmount(struct vfsmount *mnt) >  } >  EXPORT_SYMBOL(kern_unmount); >   > +static void rcu_mntput(struct rcu_head *head) > +{ > +       struct mount *mnt = container_of(head, struct mount, > mnt_rcu); > +       mntput(&mnt->mnt); > +} > + > +void kern_rcu_unmount(struct vfsmount *mnt) > +{ > +       /* release long term mount so mount point can be released */ > +       if (!IS_ERR_OR_NULL(mnt)) { > +               struct mount *m = real_mount(mnt); > +               m->mnt_ns = NULL; > +               call_rcu(&m->mnt_rcu, rcu_mntput); > +       } > +} OK, two comments here: 1) As Paul pointed out, we need to use call_rcu_work here, because rcu_mntput needs to run from a work item (or well, any process context) because of the rwlock. 2) No user of kern_unmount can use the vfsmount structure after kern_unmount returns. That means they could all use the RCU version, and no special version is needed. Let me go test a patch that does that... -- All Rights Reversed.