[PATCH] arm64: break while loop if task had been rescheduled

[PATCH] arm64: break while loop if task had been rescheduled

[tengfeif]

When task isn't current task, this task's state have
chance to be changed during printing this task's
backtrace, so it is possible that task's fp and fp+8
have the same vaule, so cannot break the while loop.
To fix this issue, we first save the task's state, sp
and fp, then we will get the task's current state, sp
and fp in each while again. we will stop to print
backtrace if we found any of the values are different
than what we saved.

/********************************answer 
question**********************************/
This is very confusing. IIUC it suggests that while printing
the backtrace for non-current tasks the do/while loop does not
exit because fp and fp+8 might have the same value ? When would
this happen ? Even in that case the commit message here does not
properly match the change in this patch.

In our issue, we got fp=pc=0xFFFFFF8025A13BA0, so cannot exit while
loop in dump_basktrace().
After analyze our issue's dump, we found one task(such as: task A)
is exiting via invoke do_exit() during another task is showing task
A's dumptask. In kernel code, do_exit() and exit_notify are defined
as follows:
void noreturn do_exit(long code)
{
      ......
      exit_notify(tsk, group_dead);
      ......
}
static void exit_notify(struct task_struct *tsk, int group_dead)
{
      ......
}
Because of exit_notify() is a static function, so it is inlined to
do_exit() when compile kernel, so we can get partial assembly code
of do_exit() as follows:
……
{
         bool autoreap;
         struct task_struct *p, *n;
         LIST_HEAD(dead);

         write_lock_irq(&tasklist_lock);
      c10:       90000000        adrp    x0, 0 <tasklist_lock>
      c14:       910003e8        mov     x8, sp
      c18:       91000000        add     x0, x0, #0x0
*/
static void exit_notify(struct task_struct *tsk, int group_dead)
{
         bool autoreap;
         struct task_struct *p, *n;
         LIST_HEAD(dead);
      c1c:       a90023e8        stp     x8, x8, [sp]

         write_lock_irq(&tasklist_lock);
      c20:       94000000        bl      0 <_raw_write_lock_irq>
      c24:       f9435268        ldr     x8, [x19,#1696]
……
 From the code "c14:" and "c1c:", we will find sp's addr value is stored
in sp and sp+8, so sp's vaule equal (sp+8)'s value.
In our issue, there is a chance of fp point sp, so there will be 
fp=pc=fp's
addr value,so code cannot break from while loop in dump_backtrace().

/********************************answer 
question**********************************/

/********************************answer 
question**********************************/
This patch tries to stop printing the stack for non-current tasks
if their state change while there is one dump_backtrace() trying
to print back trace. Dont we have any lock preventing a task in
this situation (while dumping it's backtrace) from running again
or changing state.
I haven't found any lock preventing a task in this situation, and I 
think we shouldn't
prevent task running if this task is scheduled.
/********************************answer 
question**********************************/

Signed-off-by: Tengfei Fan <tengfeif@codeaurora.org>
---
  arch/arm64/kernel/traps.c | 23 +++++++++++++++++++++++
  1 file changed, 23 insertions(+)

diff --git a/arch/arm64/kernel/traps.c b/arch/arm64/kernel/traps.c
index 2975598..9df6e02 100644
--- a/arch/arm64/kernel/traps.c
+++ b/arch/arm64/kernel/traps.c
@@ -103,6 +103,9 @@ void dump_backtrace(struct pt_regs *regs, struct 
task_struct *tsk)
  {
      struct stackframe frame;
      int skip = 0;
+    long cur_state = 0;
+    unsigned long cur_sp = 0;
+    unsigned long cur_fp = 0;

      pr_debug("%s(regs = %p tsk = %p)\n", __func__, regs, tsk);

@@ -127,6 +130,9 @@ void dump_backtrace(struct pt_regs *regs, struct 
task_struct *tsk)
           */
          frame.fp = thread_saved_fp(tsk);
          frame.pc = thread_saved_pc(tsk);
+        cur_state = tsk->state;
+        cur_sp = thread_saved_sp(tsk);
+        cur_fp = frame.fp;

/********************************answer 
question**********************************/
Should 'saved_state|sp|fp' instead as its applicable to non-current
tasks only.
'saved_state|sp|fp' only applies to non-current tasks.

/********************************answer 
question**********************************/

      }
  #ifdef CONFIG_FUNCTION_GRAPH_TRACER
      frame.graph = 0;
@@ -134,6 +140,23 @@ void dump_backtrace(struct pt_regs *regs, struct 
task_struct *tsk)

      printk("Call trace:\n");
      do {
+        if (tsk != current && (cur_state != tsk->state
+            /*
+             * We would not be printing backtrace for the task
+             * that has changed state from "saved" state to ohter
+             * state before hitting the do-while loop but after
+             * saving the current state. If task's current state
+             * not equal the "saved" state, then we may print
+             * wrong call trace or end up in infinite while loop
+             * if *(fp) and *(fp+8) are same. While the situation
+             * should be stoped once we found the task's state
+             * is changed, so we detect the task's current state,
+             * sp and fp in each while.
+             */
+            || cur_sp != thread_saved_sp(tsk)
+            || cur_fp != thread_saved_fp(tsk))) {

/********************************answer 
question**********************************/
Why does any of these three mismatches detect the problematic transition
not just the state ?
1. we can use "cur_state != tsk->state" prevent printing backtrace if 
the task's
    state is changed after "saved" task's state.
2. we can use "cur_sp != thread_saved_sp(tsk)" and "cur_fp != 
thread_saved_fp(tsk)"
    prevent printing backtrace if the task's state is changed before 
"saved" task's
    state. Because the value of "thread_saved_sp(tsk)" and 
"thread_saved_fp(tsk)"
    will not equal "saved" sp(cur_sp) and fp(cur_fp).
/********************************answer 
question**********************************/

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Re: [PATCH] arm64: break while loop if task had been rescheduled

[Mark Rutland]

Hi,

This appears to be a bizarrely formatted reply to Anshuman's questions
[1] on the first posting [2] of this patch, and as it stands, it isn't
possible to follow.

Please follow the usual mailing list ettiquette, and reply inline to
questions.

I am not going to reply further to this post, but I'll comment on the
first post.

Thanks,
Mark.

[1] https://lore.kernel.org/lkml/1558430404-4840-1-git-send-email-tengfeif@codeaurora.org/T/#m415174aacdd100f9386113ed3ae9f427a2255f8a
[2] https://lore.kernel.org/lkml/1558430404-4840-1-git-send-email-tengfeif@codeaurora.org/T/#u

On Fri, May 24, 2019 at 11:16:16AM +0800, tengfeif@codeaurora.org wrote:
> When task isn't current task, this task's state have
> chance to be changed during printing this task's
> backtrace, so it is possible that task's fp and fp+8
> have the same vaule, so cannot break the while loop.
> To fix this issue, we first save the task's state, sp
> and fp, then we will get the task's current state, sp
> and fp in each while again. we will stop to print
> backtrace if we found any of the values are different
> than what we saved.
> 
> /********************************answer
> question**********************************/
> This is very confusing. IIUC it suggests that while printing
> the backtrace for non-current tasks the do/while loop does not
> exit because fp and fp+8 might have the same value ? When would
> this happen ? Even in that case the commit message here does not
> properly match the change in this patch.

So

> 
> In our issue, we got fp=pc=0xFFFFFF8025A13BA0, so cannot exit while
> loop in dump_basktrace().
> After analyze our issue's dump, we found one task(such as: task A)
> is exiting via invoke do_exit() during another task is showing task
> A's dumptask. In kernel code, do_exit() and exit_notify are defined
> as follows:
> void noreturn do_exit(long code)
> {
>      ......
>      exit_notify(tsk, group_dead);
>      ......
> }
> static void exit_notify(struct task_struct *tsk, int group_dead)
> {
>      ......
> }
> Because of exit_notify() is a static function, so it is inlined to
> do_exit() when compile kernel, so we can get partial assembly code
> of do_exit() as follows:
> ……
> {
>         bool autoreap;
>         struct task_struct *p, *n;
>         LIST_HEAD(dead);
> 
>         write_lock_irq(&tasklist_lock);
>      c10:       90000000        adrp    x0, 0 <tasklist_lock>
>      c14:       910003e8        mov     x8, sp
>      c18:       91000000        add     x0, x0, #0x0
> */
> static void exit_notify(struct task_struct *tsk, int group_dead)
> {
>         bool autoreap;
>         struct task_struct *p, *n;
>         LIST_HEAD(dead);
>      c1c:       a90023e8        stp     x8, x8, [sp]
> 
>         write_lock_irq(&tasklist_lock);
>      c20:       94000000        bl      0 <_raw_write_lock_irq>
>      c24:       f9435268        ldr     x8, [x19,#1696]
> ……
> From the code "c14:" and "c1c:", we will find sp's addr value is stored
> in sp and sp+8, so sp's vaule equal (sp+8)'s value.
> In our issue, there is a chance of fp point sp, so there will be fp=pc=fp's
> addr value,so code cannot break from while loop in dump_backtrace().
> 
> /********************************answer
> question**********************************/
> 
> /********************************answer
> question**********************************/
> This patch tries to stop printing the stack for non-current tasks
> if their state change while there is one dump_backtrace() trying
> to print back trace. Dont we have any lock preventing a task in
> this situation (while dumping it's backtrace) from running again
> or changing state.
> I haven't found any lock preventing a task in this situation, and I think we
> shouldn't
> prevent task running if this task is scheduled.
> /********************************answer
> question**********************************/
> 
> Signed-off-by: Tengfei Fan <tengfeif@codeaurora.org>
> ---
>  arch/arm64/kernel/traps.c | 23 +++++++++++++++++++++++
>  1 file changed, 23 insertions(+)
> 
> diff --git a/arch/arm64/kernel/traps.c b/arch/arm64/kernel/traps.c
> index 2975598..9df6e02 100644
> --- a/arch/arm64/kernel/traps.c
> +++ b/arch/arm64/kernel/traps.c
> @@ -103,6 +103,9 @@ void dump_backtrace(struct pt_regs *regs, struct
> task_struct *tsk)
>  {
>      struct stackframe frame;
>      int skip = 0;
> +    long cur_state = 0;
> +    unsigned long cur_sp = 0;
> +    unsigned long cur_fp = 0;
> 
>      pr_debug("%s(regs = %p tsk = %p)\n", __func__, regs, tsk);
> 
> @@ -127,6 +130,9 @@ void dump_backtrace(struct pt_regs *regs, struct
> task_struct *tsk)
>           */
>          frame.fp = thread_saved_fp(tsk);
>          frame.pc = thread_saved_pc(tsk);
> +        cur_state = tsk->state;
> +        cur_sp = thread_saved_sp(tsk);
> +        cur_fp = frame.fp;
> 
> /********************************answer
> question**********************************/
> Should 'saved_state|sp|fp' instead as its applicable to non-current
> tasks only.
> 'saved_state|sp|fp' only applies to non-current tasks.
> 
> /********************************answer
> question**********************************/
> 
>      }
>  #ifdef CONFIG_FUNCTION_GRAPH_TRACER
>      frame.graph = 0;
> @@ -134,6 +140,23 @@ void dump_backtrace(struct pt_regs *regs, struct
> task_struct *tsk)
> 
>      printk("Call trace:\n");
>      do {
> +        if (tsk != current && (cur_state != tsk->state
> +            /*
> +             * We would not be printing backtrace for the task
> +             * that has changed state from "saved" state to ohter
> +             * state before hitting the do-while loop but after
> +             * saving the current state. If task's current state
> +             * not equal the "saved" state, then we may print
> +             * wrong call trace or end up in infinite while loop
> +             * if *(fp) and *(fp+8) are same. While the situation
> +             * should be stoped once we found the task's state
> +             * is changed, so we detect the task's current state,
> +             * sp and fp in each while.
> +             */
> +            || cur_sp != thread_saved_sp(tsk)
> +            || cur_fp != thread_saved_fp(tsk))) {
> 
> /********************************answer
> question**********************************/
> Why does any of these three mismatches detect the problematic transition
> not just the state ?
> 1. we can use "cur_state != tsk->state" prevent printing backtrace if the
> task's
>    state is changed after "saved" task's state.
> 2. we can use "cur_sp != thread_saved_sp(tsk)" and "cur_fp !=
> thread_saved_fp(tsk)"
>    prevent printing backtrace if the task's state is changed before "saved"
> task's
>    state. Because the value of "thread_saved_sp(tsk)" and
> "thread_saved_fp(tsk)"
>    will not equal "saved" sp(cur_sp) and fp(cur_fp).
> /********************************answer
> question**********************************/

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Re: [PATCH] arm64: break while loop if task had been rescheduled

[tengfeif]

On 2019-05-24 18:41, Mark Rutland wrote:
> On Tue, May 21, 2019 at 05:20:04PM +0800, Tengfei Fan wrote:
>> While printing a task's backtrace and this task isn't
>> current task, it is possible that task's fp and fp+8
>> have the same value, so cannot break the while loop.
>> This can break while loop if this task had been
>> rescheduled during print this task's backtrace.
> 
> There are a few cases where backtracing can get stuck in an infinite
> loop. I'd attempted to address that more generally in my
> arm64/robust-stacktrace branch [1].
> 
> Looking at tsk->state here is inherently racy, and doesn't solve the
> general case, so I'd prefer to avoid that.
> 
> Do my patches help you here? If so, I'm happy to rebase those to
> v5.2-rc1 and repost.

I think your arm64/robust-stacktrace branch [1] can cover my issue, 
please
rebase and reposet

Thanks,
Tengfei Fan

> 
> Thanks,
> Mark.
> 
> [1]
> https://git.kernel.org/pub/scm/linux/kernel/git/mark/linux.git/log/?h=arm64/robust-stacktrace
> 
>> 
>> Signed-off-by: Tengfei Fan <tengfeif@codeaurora.org>
>> ---
>>  arch/arm64/kernel/traps.c | 23 +++++++++++++++++++++++
>>  1 file changed, 23 insertions(+)
>> 
>> diff --git a/arch/arm64/kernel/traps.c b/arch/arm64/kernel/traps.c
>> index 2975598..9df6e02 100644
>> --- a/arch/arm64/kernel/traps.c
>> +++ b/arch/arm64/kernel/traps.c
>> @@ -103,6 +103,9 @@ void dump_backtrace(struct pt_regs *regs, struct 
>> task_struct *tsk)
>>  {
>>  	struct stackframe frame;
>>  	int skip = 0;
>> +	long cur_state = 0;
>> +	unsigned long cur_sp = 0;
>> +	unsigned long cur_fp = 0;
>> 
>>  	pr_debug("%s(regs = %p tsk = %p)\n", __func__, regs, tsk);
>> 
>> @@ -127,6 +130,9 @@ void dump_backtrace(struct pt_regs *regs, struct 
>> task_struct *tsk)
>>  		 */
>>  		frame.fp = thread_saved_fp(tsk);
>>  		frame.pc = thread_saved_pc(tsk);
>> +		cur_state = tsk->state;
>> +		cur_sp = thread_saved_sp(tsk);
>> +		cur_fp = frame.fp;
>>  	}
>>  #ifdef CONFIG_FUNCTION_GRAPH_TRACER
>>  	frame.graph = 0;
>> @@ -134,6 +140,23 @@ void dump_backtrace(struct pt_regs *regs, struct 
>> task_struct *tsk)
>> 
>>  	printk("Call trace:\n");
>>  	do {
>> +		if (tsk != current && (cur_state != tsk->state
>> +			/*
>> +			 * We would not be printing backtrace for the task
>> +			 * that has changed state from uninterruptible to
>> +			 * running before hitting the do-while loop but after
>> +			 * saving the current state. If task is in running
>> +			 * state before saving the state, then we may print
>> +			 * wrong call trace or end up in infinite while loop
>> +			 * if *(fp) and *(fp+8) are same. While the situation
>> +			 * will stop print when that task schedule out.
>> +			 */
>> +			|| cur_sp != thread_saved_sp(tsk)
>> +			|| cur_fp != thread_saved_fp(tsk))) {
>> +			printk("The task:%s had been rescheduled!\n",
>> +				tsk->comm);
>> +			break;
>> +		}
>>  		/* skip until specified stack frame */
>>  		if (!skip) {
>>  			dump_backtrace_entry(frame.pc);
>> --
>> The Qualcomm Innovation Center, Inc. is a member of the Code Aurora 
>> Forum,
>> a Linux Foundation Collaborative Project
>> 

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Re: [PATCH] arm64: break while loop if task had been rescheduled

[tengfeif]

On 2019-05-22 17:04, Anshuman Khandual wrote:
> On 05/21/2019 02:50 PM, Tengfei Fan wrote:
>> While printing a task's backtrace and this task isn't
>> current task, it is possible that task's fp and fp+8
>> have the same value, so cannot break the while loop.
>> This can break while loop if this task had been
>> rescheduled during print this task's backtrace.
> 
> This is very confusing. IIUC it suggests that while printing
> the backtrace for non-current tasks the do/while loop does not
> exit because fp and fp+8 might have the same value ? When would
> this happen ? Even in that case the commit message here does not
> properly match the change in this patch.

In our issue, we got fp=pc=0xFFFFFF8025A13BA0, so cannot exit while
loop in dump_basktrace().
After analyze our issue's dump, we found one task(such as: task A)
is exiting via invoke do_exit() during another task is showing task
A's dumptask. In kernel code, do_exit() and exit_notify are defined
as follows:
void noreturn do_exit(long code)
{
      ......
      exit_notify(tsk, group_dead);
      ......
}
static void exit_notify(struct task_struct *tsk, int group_dead)
{
      ......
}
Because of exit_notify() is a static function, so it is inlined to
do_exit() when compile kernel, so we can get partial assembly code
of do_exit() as follows:
……
{
         bool autoreap;
         struct task_struct *p, *n;
         LIST_HEAD(dead);

         write_lock_irq(&tasklist_lock);
      c10:       90000000        adrp    x0, 0 <tasklist_lock>
      c14:       910003e8        mov     x8, sp
      c18:       91000000        add     x0, x0, #0x0
*/
static void exit_notify(struct task_struct *tsk, int group_dead)
{
         bool autoreap;
         struct task_struct *p, *n;
         LIST_HEAD(dead);
      c1c:       a90023e8        stp     x8, x8, [sp]

         write_lock_irq(&tasklist_lock);
      c20:       94000000        bl      0 <_raw_write_lock_irq>
      c24:       f9435268        ldr     x8, [x19,#1696]
……
 From the code "c14:" and "c1c:", we will find sp's addr value is stored
in sp and sp+8, so sp's vaule equal (sp+8)'s value.
In our issue, there is a chance of fp point sp, so there will be 
fp=pc=fp's
addr value,so code cannot break from while loop in dump_backtrace().

> 
> This patch tries to stop printing the stack for non-current tasks
> if their state change while there is one dump_backtrace() trying
> to print back trace. Dont we have any lock preventing a task in
> this situation (while dumping it's backtrace) from running again
> or changing state.

I haven't found any lock preventing a task in this situation, and I 
think we shouldn't
prevent task running if this task is scheduled.
> 
>> 
>> Signed-off-by: Tengfei Fan <tengfeif@codeaurora.org>
>> ---
>>  arch/arm64/kernel/traps.c | 23 +++++++++++++++++++++++
>>  1 file changed, 23 insertions(+)
>> 
>> diff --git a/arch/arm64/kernel/traps.c b/arch/arm64/kernel/traps.c
>> index 2975598..9df6e02 100644
>> --- a/arch/arm64/kernel/traps.c
>> +++ b/arch/arm64/kernel/traps.c
>> @@ -103,6 +103,9 @@ void dump_backtrace(struct pt_regs *regs, struct 
>> task_struct *tsk)
>>  {
>>  	struct stackframe frame;
>>  	int skip = 0;
>> +	long cur_state = 0;
>> +	unsigned long cur_sp = 0;
>> +	unsigned long cur_fp = 0;
>> 
>>  	pr_debug("%s(regs = %p tsk = %p)\n", __func__, regs, tsk);
>> 
>> @@ -127,6 +130,9 @@ void dump_backtrace(struct pt_regs *regs, struct 
>> task_struct *tsk)
>>  		 */
>>  		frame.fp = thread_saved_fp(tsk);
>>  		frame.pc = thread_saved_pc(tsk);
>> +		cur_state = tsk->state;
>> +		cur_sp = thread_saved_sp(tsk);
>> +		cur_fp = frame.fp;
> 
> Should 'saved_state|sp|fp' instead as its applicable to non-current
> tasks only.

'saved_state|sp|fp' only applies to non-current tasks.

> 
>>  	}
>>  #ifdef CONFIG_FUNCTION_GRAPH_TRACER
>>  	frame.graph = 0;
>> @@ -134,6 +140,23 @@ void dump_backtrace(struct pt_regs *regs, struct 
>> task_struct *tsk)
>> 
>>  	printk("Call trace:\n");
>>  	do {
>> +		if (tsk != current && (cur_state != tsk->state
>> +			/*
>> +			 * We would not be printing backtrace for the task
>> +			 * that has changed state from "saved" state to other
>> +			 * state before hitting the do-while loop but after
>> +			 * saving the current state. If task's current state
> 
> This does not check any explicit task states like 'un-interruptible' or
> 'running' but instead tracks change from any previously 'saved' state.

have updated comments.
> 
> 
>> +			 * not equal the "saved" state, then we may print
>> +			 * wrong call trace or end up in infinite while loop
>> +			 * if *(fp) and *(fp+8) are same. While the situation
> 
> Then dump_backtrace() must detect it, should not save it and just 
> abort.

have updatd commentes.
> 
> 
>> +			 * should be stoped once we found the task's state
    +			 * is changed, so we detect the task's current state,
    +			 * sp and fp in each while.
> 
> Thats not a reliable solution. AFICS we should not proceed further if
> there is a chance of an wrong trace or an infinite loop. Hoping that
> the printing will stop when task gets scheduled out does not seem 
> right.

In this patch, it will break while loop and stop to print backtrace if 
we
find the task's state change or there is a chance of an infinite loop.
> 
>> +			 */
>> +			|| cur_sp != thread_saved_sp(tsk)
>> +			|| cur_fp != thread_saved_fp(tsk))) {
> 
> Why does any of these three mismatches detect the problematic 
> transition
> not just the state ?

1. we can use "cur_state != tsk->state" prevent printing backtrace if 
the task's
    state is changed after "saved" task's state.
2. we can use "cur_sp != thread_saved_sp(tsk)" and "cur_fp != 
thread_saved_fp(tsk)"
    prevent printing backtrace if the task's state is changed before 
"saved" task's
    state. Because the value of "thread_saved_sp(tsk)" and 
"thread_saved_fp(tsk)"
    will not equal "saved" sp(cur_sp) and fp(cur_fp).

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Re: [PATCH] arm64: break while loop if task had been rescheduled

[Mark Rutland]

On Tue, May 21, 2019 at 05:20:04PM +0800, Tengfei Fan wrote:
> While printing a task's backtrace and this task isn't
> current task, it is possible that task's fp and fp+8
> have the same value, so cannot break the while loop.
> This can break while loop if this task had been
> rescheduled during print this task's backtrace.

There are a few cases where backtracing can get stuck in an infinite
loop. I'd attempted to address that more generally in my
arm64/robust-stacktrace branch [1].

Looking at tsk->state here is inherently racy, and doesn't solve the
general case, so I'd prefer to avoid that.

Do my patches help you here? If so, I'm happy to rebase those to
v5.2-rc1 and repost.

Thanks,
Mark.

[1] https://git.kernel.org/pub/scm/linux/kernel/git/mark/linux.git/log/?h=arm64/robust-stacktrace

> 
> Signed-off-by: Tengfei Fan <tengfeif@codeaurora.org>
> ---
>  arch/arm64/kernel/traps.c | 23 +++++++++++++++++++++++
>  1 file changed, 23 insertions(+)
> 
> diff --git a/arch/arm64/kernel/traps.c b/arch/arm64/kernel/traps.c
> index 2975598..9df6e02 100644
> --- a/arch/arm64/kernel/traps.c
> +++ b/arch/arm64/kernel/traps.c
> @@ -103,6 +103,9 @@ void dump_backtrace(struct pt_regs *regs, struct task_struct *tsk)
>  {
>  	struct stackframe frame;
>  	int skip = 0;
> +	long cur_state = 0;
> +	unsigned long cur_sp = 0;
> +	unsigned long cur_fp = 0;
>  
>  	pr_debug("%s(regs = %p tsk = %p)\n", __func__, regs, tsk);
>  
> @@ -127,6 +130,9 @@ void dump_backtrace(struct pt_regs *regs, struct task_struct *tsk)
>  		 */
>  		frame.fp = thread_saved_fp(tsk);
>  		frame.pc = thread_saved_pc(tsk);
> +		cur_state = tsk->state;
> +		cur_sp = thread_saved_sp(tsk);
> +		cur_fp = frame.fp;
>  	}
>  #ifdef CONFIG_FUNCTION_GRAPH_TRACER
>  	frame.graph = 0;
> @@ -134,6 +140,23 @@ void dump_backtrace(struct pt_regs *regs, struct task_struct *tsk)
>  
>  	printk("Call trace:\n");
>  	do {
> +		if (tsk != current && (cur_state != tsk->state
> +			/*
> +			 * We would not be printing backtrace for the task
> +			 * that has changed state from uninterruptible to
> +			 * running before hitting the do-while loop but after
> +			 * saving the current state. If task is in running
> +			 * state before saving the state, then we may print
> +			 * wrong call trace or end up in infinite while loop
> +			 * if *(fp) and *(fp+8) are same. While the situation
> +			 * will stop print when that task schedule out.
> +			 */
> +			|| cur_sp != thread_saved_sp(tsk)
> +			|| cur_fp != thread_saved_fp(tsk))) {
> +			printk("The task:%s had been rescheduled!\n",
> +				tsk->comm);
> +			break;
> +		}
>  		/* skip until specified stack frame */
>  		if (!skip) {
>  			dump_backtrace_entry(frame.pc);
> -- 
> The Qualcomm Innovation Center, Inc. is a member of the Code Aurora Forum,
> a Linux Foundation Collaborative Project
> 

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Re: [PATCH] arm64: break while loop if task had been rescheduled

[Anshuman Khandual]

On 05/21/2019 02:50 PM, Tengfei Fan wrote:
> While printing a task's backtrace and this task isn't
> current task, it is possible that task's fp and fp+8
> have the same value, so cannot break the while loop.
> This can break while loop if this task had been
> rescheduled during print this task's backtrace.

This is very confusing. IIUC it suggests that while printing
the backtrace for non-current tasks the do/while loop does not
exit because fp and fp+8 might have the same value ? When would
this happen ? Even in that case the commit message here does not
properly match the change in this patch.

This patch tries to stop printing the stack for non-current tasks
if their state change while there is one dump_backtrace() trying
to print back trace. Dont we have any lock preventing a task in
this situation (while dumping it's backtrace) from running again
or changing state.

> 
> Signed-off-by: Tengfei Fan <tengfeif@codeaurora.org>
> ---
>  arch/arm64/kernel/traps.c | 23 +++++++++++++++++++++++
>  1 file changed, 23 insertions(+)
> 
> diff --git a/arch/arm64/kernel/traps.c b/arch/arm64/kernel/traps.c
> index 2975598..9df6e02 100644
> --- a/arch/arm64/kernel/traps.c
> +++ b/arch/arm64/kernel/traps.c
> @@ -103,6 +103,9 @@ void dump_backtrace(struct pt_regs *regs, struct task_struct *tsk)
>  {
>  	struct stackframe frame;
>  	int skip = 0;
> +	long cur_state = 0;
> +	unsigned long cur_sp = 0;
> +	unsigned long cur_fp = 0;
>  
>  	pr_debug("%s(regs = %p tsk = %p)\n", __func__, regs, tsk);
>  
> @@ -127,6 +130,9 @@ void dump_backtrace(struct pt_regs *regs, struct task_struct *tsk)
>  		 */
>  		frame.fp = thread_saved_fp(tsk);
>  		frame.pc = thread_saved_pc(tsk);
> +		cur_state = tsk->state;
> +		cur_sp = thread_saved_sp(tsk);
> +		cur_fp = frame.fp;

Should 'saved_state|sp|fp' instead as its applicable to non-current
tasks only.

>  	}
>  #ifdef CONFIG_FUNCTION_GRAPH_TRACER
>  	frame.graph = 0;
> @@ -134,6 +140,23 @@ void dump_backtrace(struct pt_regs *regs, struct task_struct *tsk)
>  
>  	printk("Call trace:\n");
>  	do {
> +		if (tsk != current && (cur_state != tsk->state
> +			/*
> +			 * We would not be printing backtrace for the task
> +			 * that has changed state from uninterruptible to
> +			 * running before hitting the do-while loop but after
> +			 * saving the current state. If task is in running

This does not check any explicit task states like 'un-interruptible' or
'running' but instead tracks change from any previously 'saved' state.


> +			 * state before saving the state, then we may print
> +			 * wrong call trace or end up in infinite while loop
> +			 * if *(fp) and *(fp+8) are same. While the situation

Then dump_backtrace() must detect it, should not save it and just abort.


> +			 * will stop print when that task schedule out.

Thats not a reliable solution. AFICS we should not proceed further if
there is a chance of an wrong trace or an infinite loop. Hoping that
the printing will stop when task gets scheduled out does not seem right.

> +			 */
> +			|| cur_sp != thread_saved_sp(tsk)
> +			|| cur_fp != thread_saved_fp(tsk))) {

Why does any of these three mismatches detect the problematic transition
not just the state ?

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[PATCH] arm64: break while loop if task had been rescheduled

[Tengfei Fan]

While printing a task's backtrace and this task isn't
current task, it is possible that task's fp and fp+8
have the same value, so cannot break the while loop.
This can break while loop if this task had been
rescheduled during print this task's backtrace.

Signed-off-by: Tengfei Fan <tengfeif@codeaurora.org>
---
 arch/arm64/kernel/traps.c | 23 +++++++++++++++++++++++
 1 file changed, 23 insertions(+)

diff --git a/arch/arm64/kernel/traps.c b/arch/arm64/kernel/traps.c
index 2975598..9df6e02 100644
--- a/arch/arm64/kernel/traps.c
+++ b/arch/arm64/kernel/traps.c
@@ -103,6 +103,9 @@ void dump_backtrace(struct pt_regs *regs, struct task_struct *tsk)
 {
 	struct stackframe frame;
 	int skip = 0;
+	long cur_state = 0;
+	unsigned long cur_sp = 0;
+	unsigned long cur_fp = 0;
 
 	pr_debug("%s(regs = %p tsk = %p)\n", __func__, regs, tsk);
 
@@ -127,6 +130,9 @@ void dump_backtrace(struct pt_regs *regs, struct task_struct *tsk)
 		 */
 		frame.fp = thread_saved_fp(tsk);
 		frame.pc = thread_saved_pc(tsk);
+		cur_state = tsk->state;
+		cur_sp = thread_saved_sp(tsk);
+		cur_fp = frame.fp;
 	}
 #ifdef CONFIG_FUNCTION_GRAPH_TRACER
 	frame.graph = 0;
@@ -134,6 +140,23 @@ void dump_backtrace(struct pt_regs *regs, struct task_struct *tsk)
 
 	printk("Call trace:\n");
 	do {
+		if (tsk != current && (cur_state != tsk->state
+			/*
+			 * We would not be printing backtrace for the task
+			 * that has changed state from uninterruptible to
+			 * running before hitting the do-while loop but after
+			 * saving the current state. If task is in running
+			 * state before saving the state, then we may print
+			 * wrong call trace or end up in infinite while loop
+			 * if *(fp) and *(fp+8) are same. While the situation
+			 * will stop print when that task schedule out.
+			 */
+			|| cur_sp != thread_saved_sp(tsk)
+			|| cur_fp != thread_saved_fp(tsk))) {
+			printk("The task:%s had been rescheduled!\n",
+				tsk->comm);
+			break;
+		}
 		/* skip until specified stack frame */
 		if (!skip) {
 			dump_backtrace_entry(frame.pc);
-- 
The Qualcomm Innovation Center, Inc. is a member of the Code Aurora Forum,
a Linux Foundation Collaborative Project


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