On 22:27 Wed 30 Oct 2019, Randy Dunlap wrote:
>On 10/30/19 9:52 PM, Bhaskar Chowdhury wrote:
>>>>> That 'rm' doesn't remove any files.  Compare what remove_old_kernel() does.
>>>> No,it is not using that function rather take the parameter from the
>>>> commandline and get into boot dir match with it and remove it.
>>>
>>> But it doesn't do that.  I tested it.  It should be more like what
>>> rmeove_old_kernel() does:
>>>
>>>         rm -If vmlinuz-$kernel_ver System.map-$kernel_ver config-$kernel_ver
>>>
>>> and if not, please explain why not.
>> Okay, again some uniformity missing in the code, I would like to your
>> suggested method,i.e call remove_old_kernel to do the job instead of depending on individual kernel.
>
>The simplest thing to do is set kernel_version=$kernel_ver
>and then call remove_old_kernel().
>And set modules_version=$modules_dir_name and call remove_old_modules_dir().
>
>But it would be cleaner to pass a parameter (kernel_version) to the
>remove_old_kernel() function and to pass a parameter (modules_dir) to the
>remove_old_modules_dir() function.

>

Thank you...I have just modified the code and call both the function
under remove option. BTW I didn't set the extra variable $kernel_ver 
name it $kernel_version and instead of $modules_dir_name name it $mo
dules_version.

Capturing command line parameter in $kernel_version and $modules_version

Is that fine? Here is a code snippet:

 -r | --remove)
   if [[ $# -ne 3 ]]; then
    printf "You need to provide kernel version and modules directory
    name \n"
    exit 1
    else
    remove_old_kernel
    remove_old_modules_dir
    fi


I have just test it and it works.


And about solitary r option without hypen is ignoring and doing nothing.

Means, if I pass ./scripts/prune-kernel r 5.3.3 

it simply ignore and does nothing.Only with the hypen it can work.

>-- 
>~Randy
>
Bhaskar