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From: Wenchao Hao <haowenchao@huawei.com>
To: "James E . J . Bottomley" <jejb@linux.ibm.com>,
	"Martin K . Petersen" <martin.petersen@oracle.com>,
	<linux-scsi@vger.kernel.org>, <linux-kernel@vger.kernel.org>
Cc: Zhiqiang Liu <liuzhiqiang26@huawei.com>,
	Wenchao Hao <haowenchao@huawei.com>
Subject: Re: [PATCH] scsi: Do not break scan luns loop if add single lun failed
Date: Wed, 12 Jan 2022 10:28:36 +0800	[thread overview]
Message-ID: <5ec37028-052c-3851-6a89-983ab5ed4ae2@huawei.com> (raw)
In-Reply-To: <20211225232911.1117843-1-haowenchao@huawei.com>

On 2021/12/26 7:29, Wenchao Hao wrote:
> Failed to add a single lun does not mean all luns are unaccessible,
> if we break the scan luns loop, the other luns reported by REPORT LUNS
> command would not be probed any more.
> 
> In this case, we might loss some luns which are accessible.
> 
> Signed-off-by: Wenchao Hao <haowenchao@huawei.com>
> ---
>   drivers/scsi/scsi_scan.c | 4 ++--
>   1 file changed, 2 insertions(+), 2 deletions(-)
> 
> diff --git a/drivers/scsi/scsi_scan.c b/drivers/scsi/scsi_scan.c
> index 23e1c0acdeae..fee7ce082103 100644
> --- a/drivers/scsi/scsi_scan.c
> +++ b/drivers/scsi/scsi_scan.c
> @@ -1476,13 +1476,13 @@ static int scsi_report_lun_scan(struct scsi_target *starget, blist_flags_t bflag
>   				lun, NULL, NULL, rescan, NULL);
>   			if (res == SCSI_SCAN_NO_RESPONSE) {
>   				/*
> -				 * Got some results, but now none, abort.
> +				 * Got some results, but now none, abort this lun
>   				 */
>   				sdev_printk(KERN_ERR, sdev,
>   					"Unexpected response"
>   					" from lun %llu while scanning, scan"
>   					" aborted\n", (unsigned long long)lun);
> -				break;
> +				continue;
>   			}
>   		}
>   	}
> 

ping ...

      parent reply	other threads:[~2022-01-12  2:28 UTC|newest]

Thread overview: 4+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2021-12-25 23:29 [PATCH] scsi: Do not break scan luns loop if add single lun failed Wenchao Hao
2021-12-30 17:55 ` Steffen Maier
2022-01-04 12:10   ` Wenchao Hao
2022-01-12  2:28 ` Wenchao Hao [this message]

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