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Subject: Re: m68k: Convert to genirq (WIP)
From: Geert Uytterhoeven <geert@linux-m68k.org>
To: Finn Thain <fthain@telegraphics.com.au>
Cc: Brad Boyer <flar@allandria.com>, "Linux/m68k" <linux-m68k@vger.kernel.org>,
        Thomas Gleixner <tglx@linutronix.de>,
        Linux Kernel Development <linux-kernel@vger.kernel.org>
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On Wed, Aug 10, 2011 at 12:53, Finn Thain <fthain@telegraphics.com.au> wrote:
>> via1_irq
>>     OSS_IRQLEV_VIA1 = IRQ_AUTO_6 (on oss)       conflict: psc_irq
>>
>>     IRQ_AUTO_1                                  conflict: iop_ism_irq

>> iop_ism_irq
>>     OSS_IRQLEV_IOPISM = 1 = IRQ_AUTO_1 (on oss) conflict: via1_irq
>
> via1_irq is remapped to IRQ_AUTO_6 on OSS.

According to via_register_interrupts(), it requests both:

        if (via_alt_mapping) {
                if (request_irq(IRQ_AUTO_1, via1_irq, 0, "software",
                                (void *)via1))
                        pr_err("Couldn't register %s interrupt\n", "software");
                if (request_irq(IRQ_AUTO_6, via1_irq, 0, "via1", (void *)via1))
                        pr_err("Couldn't register %s interrupt\n", "via1");
        } else {
                if (request_irq(IRQ_AUTO_1, via1_irq, 0, "via1", (void *)via1))
                        pr_err("Couldn't register %s interrupt\n", "via1");
        }

Hence IRQ_AUTO_1 must be shared, and we cannot use an optimized chain
handler for via1_irq() nor iop_ism_irq(). This is the only remaining conflict
I see.

Gr{oetje,eeting}s,

                        Geert

--
Geert Uytterhoeven -- There's lots of Linux beyond ia32 -- geert@linux-m68k.org

In personal conversations with technical people, I call myself a hacker. But
when I'm talking to journalists I just say "programmer" or something like that.
                                -- Linus Torvalds