From mboxrd@z Thu Jan 1 00:00:00 1970 From: Eliezer Tamir Subject: Re: [PATCH net-next] net: rename low latency sockets functions to busy poll Date: Mon, 08 Jul 2013 22:46:04 +0300 Message-ID: <51DB16FC.7060003@linux.intel.com> References: <20130708132034.17639.4396.stgit@ladj378.jer.intel.com> <51DAF373.4040606@linux.intel.com> Mime-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 7bit Cc: David Miller , Linux Kernel Mailing List , Network Development , Andrew Morton , David Woodhouse , Eliezer Tamir To: Linus Torvalds Return-path: In-Reply-To: Sender: linux-kernel-owner@vger.kernel.org List-Id: netdev.vger.kernel.org On 08/07/2013 22:37, Linus Torvalds wrote: > On Mon, Jul 8, 2013 at 10:14 AM, Eliezer Tamir > wrote: >> >> I think there is no way for the compiler to know the value of >> can_busy_loop at compile time. It depends on the replies we get >> from polling the sockets. ll_flag was there to make sure the compiler >> will know when things are defined out. > > No, my point was that we want to handle the easily seen register test > first, and not even have to load current(). > > The compiler may end up scheduling the code to load current anyway, > but the way you wrote it it's pretty much guaranteed that it will do > it. I see. OK. > In fact, I'd argue for initializing start_time to zero, and have the > "have we timed out" logic load it only if necessary, rather than > initializing it based on whether POLL_BUSY_WAIT was set or not. > Because one common case - even with POLL_BUSY_WAIT - is that we go > through the loop exactly once, and the data exists on the very first > try. And that is in fact the case we want to optimize and not do any > extra work for at all. > > So I would actually argue that the whole timeout code might as well be > something like > > unsigned long start_time = 0; > ... > if (want_busy_poll && !need_resched()) { > unsigned long now = busy_poll_sched_clock(); > if (!start_time) { > start_time = now + sysctl.busypoll; > continue; > } > if (time_before(start_time, now)) > continue; > } > OK. Thanks, Eliezer