From mboxrd@z Thu Jan 1 00:00:00 1970 From: Julia Lawall Subject: Re: [PATCH v2 1/6] net-PPP: Replacement of a printk() call by pr_warn() in mppe_rekey() Date: Sun, 7 Dec 2014 11:44:42 +0100 (CET) Message-ID: References: <1417731809.2721.17.camel@perches.com> <1417765287.2721.39.camel@perches.com> Mime-Version: 1.0 Content-Type: TEXT/PLAIN; charset=US-ASCII Cc: SF Markus Elfring , Sergei Shtylyov , Paul Mackerras , linux-ppp@vger.kernel.org, netdev@vger.kernel.org, Eric Dumazet , LKML , kernel-janitors@vger.kernel.org To: Joe Perches Return-path: In-Reply-To: <1417765287.2721.39.camel@perches.com> Sender: linux-ppp-owner@vger.kernel.org List-Id: netdev.vger.kernel.org > A negative to that approach is inlined functions would > take the function name of the parent not keep the > inlined function name. I tried the following: #include inline int foo() { printf("%s %x\n",__func__,0x12345); } int main () { foo(); } The assembly code generated for main is: 0000000000400470
: 400470: b9 45 23 01 00 mov $0x12345,%ecx 400475: ba 4b 06 40 00 mov $0x40064b,%edx 40047a: be 44 06 40 00 mov $0x400644,%esi 40047f: bf 01 00 00 00 mov $0x1,%edi 400484: 31 c0 xor %eax,%eax 400486: e9 d5 ff ff ff jmpq 400460 <__printf_chk@plt> That is, the call to foo seems tom be inlined. But the output is: foo 12345 So it seems that __func__ is determined before inlining. julia