Re: Race condition in overlayed qcow2?

[dovgaluk <dovgaluk@ispras.ru>]

Vladimir Sementsov-Ogievskiy писал 2020-02-25 10:27:
> 25.02.2020 8:58, dovgaluk wrote:
>> Vladimir Sementsov-Ogievskiy писал 2020-02-21 16:23:
>>> 21.02.2020 15:35, dovgaluk wrote:
>>>> Vladimir Sementsov-Ogievskiy писал 2020-02-21 13:09:
>>>>> 21.02.2020 12:49, dovgaluk wrote:
>>>>>> Vladimir Sementsov-Ogievskiy писал 2020-02-20 12:36:
>>>>> 
>>>>> So, preadv in file-posix.c returns different results for the same
>>>>> offset, for file which is always opened in RO mode? Sounds 
>>>>> impossible
>>>>> :)
>>>> 
>>>> True.
>>>> Maybe my logging is wrong?
>>>> 
>>>> static ssize_t
>>>> qemu_preadv(int fd, const struct iovec *iov, int nr_iov, off_t 
>>>> offset)
>>>> {
>>>>      ssize_t res = preadv(fd, iov, nr_iov, offset);
>>>>      qemu_log("preadv %x %"PRIx64"\n", fd, (uint64_t)offset);
>>>>      int i;
>>>>      uint32_t sum = 0;
>>>>      int cnt = 0;
>>>>      for (i = 0 ; i < nr_iov ; ++i) {
>>>>          int j;
>>>>          for (j = 0 ; j < (int)iov[i].iov_len ; ++j)
>>>>          {
>>>>              sum += ((uint8_t*)iov[i].iov_base)[j];
>>>>              ++cnt;
>>>>          }
>>>>      }
>>>>      qemu_log("size: %x sum: %x\n", cnt, sum);
>>>>      assert(cnt == res);
>>>>      return res;
>>>> }
>>>> 
>>> 
>>> Hmm, I don't see any issues here..
>>> 
>>> Are you absolutely sure, that all these reads are from backing file,
>>> which is read-only and never changed (may be by other processes)?
>> 
>> Yes, I made a copy and compared the files with binwalk.
>> 
>>> 2. guest modifies buffers during operation (you can catch it if
>>> allocate personal buffer for preadv, than calculate checksum, then
>>> memcpy to guest buffer)
>> 
>> I added the following to the qemu_preadv:
>> 
>>      // do it again
>>      unsigned char *buf = g_malloc(cnt);
>>      struct iovec v = {buf, cnt};
>>      res = preadv(fd, &v, 1, offset);
>>      assert(cnt == res);
>>      uint32_t sum2 = 0;
>>      for (i = 0 ; i < cnt ; ++i)
>>          sum2 += buf[i];
>>      g_free(buf);
>>      qemu_log("--- sum2 = %x\n", sum2);
>>      assert(sum2 == sum);
>> 
>> These two reads give different results.
>> But who can modify the buffer while qcow2 workers filling it with data 
>> from the disk?
>> 
> 
> As far as I know, it's guest's buffer, and guest may modify it during
> the operation. So, it may be winxp :)

True, but normally the guest won't do it.

But I noticed that DMA operation which causes the problems has the 
following set of the buffers:
dma read sg size 20000 offset: c000fe00
--- sg: base: 2eb1000 len: 1000
--- sg: base: 3000000 len: 1000
--- sg: base: 2eb2000 len: 3000
--- sg: base: 3000000 len: 1000
--- sg: base: 2eb5000 len: b000
--- sg: base: 3040000 len: 1000
--- sg: base: 2f41000 len: 3000
--- sg: base: 3000000 len: 1000
--- sg: base: 2f44000 len: 4000
--- sg: base: 3000000 len: 1000
--- sg: base: 2f48000 len: 2000
--- sg: base: 3000000 len: 1000
--- sg: base: 3000000 len: 1000
--- sg: base: 3000000 len: 1000


It means that one DMA transaction performs multiple reads into the same 
address.
And no races is possible, when there is only one qcow2 worker.
When there are many of them - they can fill this buffer simultaneously.

Pavel Dovgalyuk