bug:git-check-ignore exit status is wrong for negative patterns when -v option used

[Jeremy Faith <jeremy.faith@jci.com>]

Hi,

git version 2.31.1.362.g311531c9de
git-check-ignore 
When a negative pattern is the last .gitignore match the -v option causes the exit status to be 0 rather than the expected 1.
e.g say .gitignore contains  one line: !hello
git check-ignore hello #outputs nothing
echo $?  #shows correct exit status=1 i.e None of the provided paths are ignored.
but
git check-ignore -v hello #output is next line
.gitignore:4:!hello	hello
echo $?  #shows wrong exit status=0 i.e. One or more of the provided paths is ignored

Following change seems to fix it for me
--- a/builtin/check-ignore.c
+++ b/builtin/check-ignore.c
@@ -114,7 +114,7 @@ static int check_ignore(struct dir_struct *dir,
                }
                if (!quiet && (pattern || show_non_matching))
                        output_pattern(pathspec.items[i].original, pattern);
-               if (pattern)
+               if (pattern && !(pattern->flags & PATTERN_FLAG_NEGATIVE))
                        num_ignored++;
        }
        free(seen);

Regards,
Jeremy Faith