* tick_setup_device in tick_common.c
@ 2011-07-02 9:47 Chao Xie
2011-07-04 2:29 ` Chao Xie
0 siblings, 1 reply; 2+ messages in thread
From: Chao Xie @ 2011-07-02 9:47 UTC (permalink / raw)
To: linux-kernel
hi
I am very strange about this function.
In this function, it has
/*
* When the device is not per cpu, pin the interrupt to the
* current cpu:
*/
if (!cpumask_equal(newdev->cpumask, cpumask))
irq_set_affinity(newdev->irq, cpumask);
When the clock event device has cpu_mask set to be cpumask_of(1), it
means that the device is bound to cpu1. So above code has covered it,
but why we have "!cpumask_equal(newdev->cpumask, cpumask)"?
if the "newdev->cpumask" equals "cpumask", cpumask_equal will return
1, and at this situation we will set the irq affinity because the
device is bound to the dedicated cpu.
Is there a bug, or i understand wrong about cpumask of clock_event_device?
Thanks.
^ permalink raw reply [flat|nested] 2+ messages in thread
* tick_setup_device in tick_common.c
2011-07-02 9:47 tick_setup_device in tick_common.c Chao Xie
@ 2011-07-04 2:29 ` Chao Xie
0 siblings, 0 replies; 2+ messages in thread
From: Chao Xie @ 2011-07-04 2:29 UTC (permalink / raw)
To: tglx, mingo; +Cc: linux-kernel
hi
I am very strange about this function.
In this function, it has
/*
* When the device is not per cpu, pin the interrupt to the
* current cpu:
*/
if (!cpumask_equal(newdev->cpumask, cpumask))
irq_set_affinity(newdev->irq, cpumask);
When the clock event device has cpu_mask set to be cpumask_of(1), it
means that the device is bound to cpu1. So above code has covered it,
but why we have "!cpumask_equal(newdev->cpumask, cpumask)"?
if the "newdev->cpumask" equals "cpumask", cpumask_equal will return
1, and at this situation we will set the irq affinity because the
device is bound to the dedicated cpu.
Is there a bug, or i understand wrong about cpumask of clock_event_device?
Thanks.
^ permalink raw reply [flat|nested] 2+ messages in thread
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2011-07-02 9:47 tick_setup_device in tick_common.c Chao Xie
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