* [Xenomai-help] Semaphore Task
@ 2007-02-28 9:17 Preetam Joshi
2007-02-28 9:30 ` Jan Kiszka
2007-02-28 9:35 ` Dmitry Adamushko
0 siblings, 2 replies; 3+ messages in thread
From: Preetam Joshi @ 2007-02-28 9:17 UTC (permalink / raw)
To: xenomai-help
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Hi i have a problem in my code the rt_sem_create calls returns a negative
value i.e. -17
THat is semaphore creation fails? Why is it so?
Here is the code that i am trying to execute. I have created semaphore in
the main routine.
#include <stdio.h>
#include <unistd.h>
#include <sys/mman.h>
#include <native/task.h>
#include <native/timer.h>
#include <native/sem.h>
RT_TASK task1;
RT_TASK task2;
RT_SEM sem1;
int i,res;
void low_task(void *arg)
{
printf("Inside the low priority task\n");
rt_sem_p(&sem1,300000000);
printf("I have the semaphore released by the high task\n");
}
void high_task(void *arg)
{
printf("Inside the high priority task \n");
res =rt_sem_p(&sem1,TM_INFINITE);
printf("%d\n", res);
if(res == 0)
{
printf("Semaphore Acquired by High task");
}
rt_task_sleep(3000000000);
rt_sem_v(&sem1);
printf("I have released the semaphore : High\n");
}
int main()
{
int res;
mlockall(MCL_CURRENT|MCL_FUTURE);
rt_task_create(&task2, "High Priority Task2", 0, 98, 0);
rt_task_create(&task1, "Low Priority Task1", 0, 5, 0);
res = rt_sem_create(&sem1, "Semaphore1", 0, S_PRIO);
printf("%d\n",res);
rt_task_start(&task2, &high_task, NULL);
rt_task_start(&task1, &low_task, NULL);
pause();
rt_task_join(&task1);
rt_task_join(&task2);
}
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^ permalink raw reply [flat|nested] 3+ messages in thread
* Re: [Xenomai-help] Semaphore Task
2007-02-28 9:17 [Xenomai-help] Semaphore Task Preetam Joshi
@ 2007-02-28 9:30 ` Jan Kiszka
2007-02-28 9:35 ` Dmitry Adamushko
1 sibling, 0 replies; 3+ messages in thread
From: Jan Kiszka @ 2007-02-28 9:30 UTC (permalink / raw)
To: Preetam Joshi; +Cc: xenomai-help
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Preetam Joshi wrote:
> Hi i have a problem in my code the rt_sem_create calls returns a negative
> value i.e. -17
>
http://www.xenomai.org/index.php/Resolving_Error_Codes
> THat is semaphore creation fails? Why is it so?
Leftover registered name from a previous run? You are not cleaning up
the semaphore on termination. See /proc/xenomai/registry.
Jan
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^ permalink raw reply [flat|nested] 3+ messages in thread
* Re: [Xenomai-help] Semaphore Task
2007-02-28 9:17 [Xenomai-help] Semaphore Task Preetam Joshi
2007-02-28 9:30 ` Jan Kiszka
@ 2007-02-28 9:35 ` Dmitry Adamushko
1 sibling, 0 replies; 3+ messages in thread
From: Dmitry Adamushko @ 2007-02-28 9:35 UTC (permalink / raw)
To: Preetam Joshi; +Cc: Xenomai help
On 28/02/07, Preetam Joshi <j.preetam@domain.hid> wrote:
> Hi i have a problem in my code the rt_sem_create calls returns a negative
> value i.e. -17
>
> THat is semaphore creation fails? Why is it so?
rt_sem_create()'s docs describe all the possible return values. -17 ==
-EEXIST (it's one of the possible errno values you may find in the
standard libc include files).
What probably happens in your case is as described below:
(look at the section for semaphores in /proc/xenomai/registry/)
-----------------------------------------------
> 1. On program start after previous crash i unable to create named mutex,
> because it [-EEXIST], after bind it's unable to operate with it because
> it locked by task from early died program, i have to restart computer.
> Any suggestions?
Something like this would do:
if (rt_mutex_bind("...", &desc) == 0)
rt_mutex_delete(&desc);
rt_mutex_create("...", &desc);
--
Best regards,
Dmitry Adamushko
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2007-02-28 9:17 [Xenomai-help] Semaphore Task Preetam Joshi
2007-02-28 9:30 ` Jan Kiszka
2007-02-28 9:35 ` Dmitry Adamushko
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