* strtok: posturing: Last item is returned as delimited, even if it is not.
@ 2015-10-30 22:43 Mike Mestnik
0 siblings, 0 replies; only message in thread
From: Mike Mestnik @ 2015-10-30 22:43 UTC (permalink / raw)
To: mtk.manpages-Re5JQEeQqe8AvxtiuMwx3w; +Cc: linux-man-u79uwXL29TY76Z2rM5mHXA
github reference:
https://github.com/cheako/ihlt/commit/ecf0b29fdb0aa127a555f2fafa57f194563e4ed2#diff-0235f01a49d01b35e981a41f59a9d2d6R48
an example client, illustrates the desired effect:
https://github.com/cheako/ihlt/commit/8f8eb2222a5ee6cb62f901afc6d2232d8c6f9b47#diff-6fbb7f44f186dbc200f4f149d8c13132R49
effect:
s/ +/,/g, s/[\r\n]+/!\n/g
Despite the working code that illustrates that strtok does tokenize
the last part of a string that's not delimited, the man page does not
address the possibility, instead it indicates that tokens must be
delimited.
Note: URIs with line numbers would be helpful.
http://man7.org/linux/man-pages/man3/strtok.3.html
"The start of the
next token is determined by scanning forward for the next
nondelimiter byte in str. If such a byte is found, it is taken as
the start of the next token. If no such byte is found, then there
are no more tokens, and strtok() returns NULL."
This would be more accurate:
The start of the
next token is determined by scanning forward for the next
nondelimiter byte in str. If such a byte is found, it is taken as
the start of the next token.
I'm unsure of how this situation can be explained, it creates a mess
of code attempting to use strtok. In my example the for loop is what
I consider upside down and it's just plain uggly hack to discover if
the token found was the end of the string and not a token.
Cheers.
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