Re: Litmus test for question from Al Viro

[Al Viro <viro@zeniv.linux.org.uk>]

On Thu, Oct 01, 2020 at 02:39:25PM -0400, Alan Stern wrote:

> The problem with a plain write is that it isn't guaranteed to be atomic 
> in any sense.  In principle, the compiler could generate code for CPU1 
> which would write 0 to V->A more than once.
> 
> Although I strongly doubt that any real compiler would actually do this, 
> the memory model does allow for it, out of an overabundance of caution.  

Point...  OK, not a problem - actually there will be WRITE_ONCE() for other
reasons; the real-life (pseudo-)code is
        spin_lock(&file->f_lock);
        to_free = NULL;
        head = file->f_ep;
        if (head->first == &epitem->fllink && epitem->fllink.next == NULL) {
		/* the set will go empty */
                file->f_ep = NULL;
                if (!is_file_epoll(file)) {
			/*
			 * not embedded into struct eventpoll; we want it
			 * freed unless it's on the check list, in which
			 * case we leave it for reverse path check to free.
			 */
                        v = container_of(head, struct ep_head, epitems);
                        if (!smp_load_acquire(&v->next))
                                to_free = v;
                }
        }
        hlist_del_rcu(&epitem->fllink);
        spin_unlock(file->f_lock);
        kfree(to_free);
and hlist_del_rcu() will use WRITE_ONCE() to store the updated forward links.

That goes into ep_remove() and CPU1 side of that thing is the final (set-emptying)
call.  CPU2 side is the list traversal step in reverse_path_check() and
in clear_tfile_check_list():
	// under rcu_read_lock()
        to_free = head;
        epitem = rcu_dereference(hlist_first_rcu(&head->epitems));
        if (epitem) {
                spin_lock(&epitem->file->f_lock);
                if (!hlist_empty(&head->epitems))
                        to_free = NULL;
                head->next = NULL;
                spin_unlock(&epitem->file->f_lock);
        }
        kfree(to_free);