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* [PATCH v3] ptrace: disable single step in __ptrace_unlink for protecting init task
@ 2022-10-26  5:29 chen zhang
  2022-10-26 13:55 ` Oleg Nesterov
  0 siblings, 1 reply; 2+ messages in thread
From: chen zhang @ 2022-10-26  5:29 UTC (permalink / raw)
  To: oleg; +Cc: chenzhang_0901, linux-kernel, chen zhang

I got below panic when doing fuzz test:

Kernel panic - not syncing: Attempted to kill init! exitcode=0x00000005
CPU: 2 PID: 1 Comm: systemd Kdump: loaded Not tainted 6.1.0-rc1 #1
Hardware name: LENOVO 20L5A07XCD/20L5A07XCD, BIOS N24ET56W (1.31 ) 02/19/2020
Call Trace:
[  157.210356]  dump_stack_lvl+0x49/0x63
[  157.210364]  dump_stack+0x10/0x16
[  157.210368]  panic+0x10c/0x299
[  157.210375]  do_exit.cold+0x15/0x15
[  157.210381]  do_group_exit+0x35/0x90
[  157.210386]  get_signal+0x910/0x960
[  157.210390]  ? signal_wake_up_state+0x2e/0x40
[  157.210396]  ? complete_signal+0xd0/0x2c0
[  157.210402]  arch_do_signal_or_restart+0x37/0x7c0
[  157.210408]  ? send_signal_locked+0xf5/0x140
[  157.210416]  exit_to_user_mode_prepare+0x133/0x180
[  157.210423]  irqentry_exit_to_user_mode+0x9/0x20
[  157.210428]  noist_exc_debug+0xea/0x150
[  157.210433]  asm_exc_debug+0x34/0x40
[  157.210438] RIP: 0033:0x7fcf2a8e51c9
[  157.210442] Code: ff ff 73 01 c3 48 8b 0d c5 7c 0c 00 f7 d8 64 89 01 48 83 c8 ff c3 66 2e 0f 1f 84 00 00 00 00 00 90 f3 0f 1e fa b8 ba 00 00 00 <0f> 05 c3 0f 1f 40 00 f3 0f 1e fa b8 ea 00 00 00 0f 05 48 3d 01 f0
[  157.210446] RSP: 002b:00007ffd7dc44678 EFLAGS: 00000302
[  157.210451] RAX: 00000000000000ba RBX: 000055f7c0363170 RCX: 000055f7c04d2820
[  157.210454] RDX: 00000000ffffffff RSI: ffffffffffffffff RDI: 000055f7c0363170
[  157.210457] RBP: 0000000000000001 R08: 0000000000000000 R09: 0000000000001dd0
[  157.210460] R10: 00007ffd7ddc9090 R11: 000000000000d7da R12: 0000000000000001
[  157.210463] R13: ffffffffffffffff R14: 000055f7bf3557c1 R15: 0000000000000000

If a task attaches init task and is single stepping it, when this task
exits, ptrace value will be cleaned. It causes SIGNAL_UNKILLABLE flag
cleaned, and init task will lose the protection. Init task maybe be killed
by SIGTRAP signal because of stepping enabled. So syscall tracing and
stepping should be turned off for protecting init task before ptrace value
is cleaned.

Signed-off-by: chen zhang <chenzhang@kylinos.cn>
---
change for v2: remove _TIF_SINGLESTEP because of some architecture has not defined _TIF_SINGLESTEP such as mips.
 
change for v3: 
Thanks for your reply and your patience. Let us discuss if the patch is useful to avoid kernel panic. In my x86 machine, 
I tested v5.4.18 kernel version, v5.15.67 kernel version and v6.1.0-rc1 kernel version.
My test C codes include:
  r[3] = 1;
  syscall(__NR_ptrace, 0x4206, r[3], 0, 0);
  syscall(__NR_ptrace, 0x4207, r[3]);
  syscall(__NR_ptrace, 9, r[3], 0, 0);
I tested while(1) loop and ctrl-c operation, fork and call ptrace syscall, loop 100 times syscalls and so on. The kernel will be in panic.
For example in 5.4 kernel, trap signal is sent by two pathes:
the one is:
	force_sig_info_to_task.cold+0x71/0x76
	force_sig_fault+0x63/0x80
	send_sigtrap+0x45/0x50
	do_debug+0x170/0x210
	debug+0x3f/0x60
	debug+0x53/0x60
the other one is:
	force_sig_info_to_task.cold+0x84/0x8e
	force_sig_fault+0x63/0x80
	user_single_step_report+0x49/0x50
	syscall_slow_exit_work+0x75/0x150
	do_syscall_64+0x156/0x190
	entry_SYSCALL_64_after_hwframe+0x44/0xa9
I debugged the sigtrap sending and get_signal function. When the debugger exits, the first sigtrap 
is prevent by SIGNAL_UNKILLABLE flag in get_signal function. Without my patch, the second sigtrap will be sent, 
and kernel will be in panic. 
I added my patch into the kernel:
+	if (unlikely(child->signal->flags & SIGNAL_UNKILLABLE) &&
+	    unlikely(task_thread_info(child)->flags & _TIF_SINGLESTEP))
+		user_disable_single_step(child);
I test the kernel with my patch, the kernel will not be in panic when I run my test program or ctrl-c the test program.
So I think my patch is efficient to avoid kernel panic. You said:
- debugger does ptrace(PTRACE_SINGLESTEP), this wakes the tracee up
- the tracee enters force_sig_info_to_task(SIGTRAP) after single step
- debugger exits, __ptrace_unlink() clears ptrace/TIF_SINGLESTEP
- force_sig_info_to_task() clears SIGNAL_UNKILLABLE, the traced init will be killed.

But run kernel with my patch, I can not find SIGTRAP signal without SIGNAL_UNKILLABLE flag for init task in get_signal function,
so the kernel can not be in panic. Please let me verify my patch, I write a simple test, test.c includes
  r[3] = 1;
  syscall(__NR_ptrace, 0x4206, r[3], 0, 0);  /* ptrace(PTRACE_SEIZE, 1, NULL, 0) */
  syscall(__NR_ptrace, 0x4207, r[3]);		/* ptrace(PTRACE_INTERRUPT, 1) */	
  syscall(__NR_ptrace, 9, r[3], 0, 0);		/* ptrace(PTRACE_SINGLESTEP, 1, NULL, 0) */
  syscall(__NR_ptrace, 9, r[3], 0, 0);		/* ptrace(PTRACE_SINGLESTEP, 1, NULL, 0) */
  sleep(10000);
When test is sleeping, I will ctrl-c to stop the test. Do you think the traced init will be killed by SIGTRAP and my patch is unuseful?
For verify my patch, I add three debug in the kernel of 6.1.0-rc1:
1. kernel/ptrace.c
printk("user_disable_single_step will be called in __ptrace_unlink, child is %s, parent is %s, cpu is %d\n",
child->comm, child->parent->comm, smp_processor_id());
2. kernel/signal.c
bool get_signal(struct ksignal *ksig) {
	...
	/* Trace actually delivered signals. */
	trace_signal_deliver(signr, &ksig->info, ka);
	/* chen zhang add */
	if (current->pid == 1 && signr == 5) {
		printk("current->siganl->flags is 0x%x,current->parent is %s, ptrace is %d, cpu is %d in get_signal\n",
			current->signal->flags, current->parent->comm, current->ptrace, smp_processor_id());
		if (unlikely(signal->flags & SIGNAL_UNKILLABLE) &&
				!sig_kernel_only(signr))
			printk("flages is SIGNAL_UNKILLABLE in get_signal\n");
		else
			printk("SIGNAL_UNKILLABLE is clear in get_signal\n");
		
		
	}
	/* chen zhang add end */
	if (!signr)
		break; /* will return 0 */
	...
	
}
3. kernel/signal.c
static int
force_sig_info_to_task(struct kernel_siginfo *info, struct task_struct *t,
	enum sig_handler handler) {
	...
	/* chen zhang add */
	if (t->pid == 1 && sig == 5) {
		printk("init will send sigtrap in force_sig_info_to_task, ptrace is %d, parent is %s,"
			"regs eflags is 0x%lx, thread info flags is 0x%lx, cpu is %d\n",
			t->ptrace,t->parent->comm,task_pt_regs(t)->flags,
			task_thread_info(t)->flags,smp_processor_id());
	}
	/* chen zhang add end */	
	if (action->sa.sa_handler == SIG_DFL &&
	    (!t->ptrace || (handler == HANDLER_EXIT))) {
	    	/* chen zhang add */
	    	printk("SIGNAL_UNKILLABLE will be clear in force_sig_info_to_task, pid is %d, sig is %d\n", t->pid, sig);
	    	/* chen zhang add end */
		t->signal->flags &= ~SIGNAL_UNKILLABLE;
	}
	ret = send_signal_locked(sig, info, t, PIDTYPE_PID);
	...
}
I installed the debug kernel with my patch and run strace ./test, dmesg:
[  768.416269] init will send sigtrap in force_sig_info_to_task, ptrace is 65537, parent is test,regs eflags is 0x306, thread info flags is 0x1000010, cpu is 1
[  768.416288] init will send sigtrap in force_sig_info_to_task, ptrace is 65537, parent is test,regs eflags is 0x306, thread info flags is 0x1000010, cpu is 1
After ctrl-c
[  780.963530] user_disable_single_step will be called in __ptrace_unlink, child is systemd, parent is swapper/0, cpu is 5
[  780.963580] current->siganl->flags is 0x40,current->parent is swapper/0, ptrace is 0, cpu is 6 in get_signal
[  780.963583] flages is SIGNAL_UNKILLABLE in get_signal

Kernel is not in panic. I also use orignal test program, it autogenerated by syzkaller. And it use fork and while(1) loop. 
When it run, the orignal kernel of v6.1.0-rc1 without my patch must be appear panic immediately.
Now test my kernel, ./err_orig, run two minutes, then ctrl+c stop it, tail of dmesg:
[ 1993.688471] user_disable_single_step will be called in __ptrace_unlink, child is systemd, parent is swapper/0, cpu is 0
[ 1993.688514] current->siganl->flags is 0x40,current->parent is swapper/0, ptrace is 0, cpu is 7 in get_signal
[ 1993.688516] flages is SIGNAL_UNKILLABLE in get_signal
[ 1993.724130] init will send sigtrap in force_sig_info_to_task, ptrace is 65537, parent is err_orig,regs eflags is 0x306, thread info flags is 0x1000010, cpu is 1
[ 1993.724299] user_disable_single_step will be called in __ptrace_unlink, child is systemd, parent is swapper/0, cpu is 5
[ 1993.724367] current->siganl->flags is 0x40,current->parent is swapper/0, ptrace is 0, cpu is 2 in get_signal
[ 1993.724372] flages is SIGNAL_UNKILLABLE in get_signal
 
It seemed running well and no kernel panic happened, SIGNAL_UNKILLABLE flag always protected the init task. My patch disabled
hardware debug on time and avoid many SIGTRIP signals to be created and sent. So my patch is useful and it can avoid kernel 
panic. At last I expect and welcome you review and verify my patch on your x86 machine. You can also give me a test case that 
can cause kernel panic, I will test it on my kernel. Thanks again!

---
 kernel/ptrace.c | 3 +++
 1 file changed, 3 insertions(+)

diff --git a/kernel/ptrace.c b/kernel/ptrace.c
index 54482193e1ed..e7c41154b31e 100644
--- a/kernel/ptrace.c
+++ b/kernel/ptrace.c
@@ -130,6 +130,9 @@ void __ptrace_unlink(struct task_struct *child)
 	put_cred(old_cred);
 
 	spin_lock(&child->sighand->siglock);
+	if (unlikely(child->signal->flags & SIGNAL_UNKILLABLE) &&
+	    unlikely(task_thread_info(child)->flags & _TIF_SINGLESTEP))
+		user_disable_single_step(child);
 	child->ptrace = 0;
 	/*
 	 * Clear all pending traps and TRAPPING.  TRAPPING should be
-- 
2.25.1


^ permalink raw reply related	[flat|nested] 2+ messages in thread

* Re: [PATCH v3] ptrace: disable single step in __ptrace_unlink for protecting init task
  2022-10-26  5:29 [PATCH v3] ptrace: disable single step in __ptrace_unlink for protecting init task chen zhang
@ 2022-10-26 13:55 ` Oleg Nesterov
  0 siblings, 0 replies; 2+ messages in thread
From: Oleg Nesterov @ 2022-10-26 13:55 UTC (permalink / raw)
  To: chen zhang; +Cc: chenzhang_0901, linux-kernel

Chen,

I do not know what can I add to our discussion. Let me repeat once again
to summarize:

	- I don't think this patch makes a lot of sense. If debugger
	  exits without PTRACE_DETACH it can crash the tracee in many
	  ways, even without PTRACE_SINGLESTEP.

	- The patch is wrong in any case. If __ptrace_unlink() is called
	  by the exiting debugger, the child can be running. In this case
	  we can't use user_disable_single_step(child), it assumes this
	  child is frozen.

	- Even if the change in __ptrace_unlink() was correct, it is racy.
	  __ptrace_unlink()->user_disable_single_step() can be called after
	  force_sig_info_to_task() was already called, but before it takes
	  ->siglock and checks ->ptrace. In this case ->ptrace will be zero
	  and SIGNAL_UNKILLABLE will be cleared.

Oh. but I already said this all, but you seem to ignore. You simply keep
sending the same patch without addressing my objections. So I wrote this
stupid test-case:

	#include <stdio.h>
	#include <unistd.h>
	#include <sys/ptrace.h>
	#include <sys/wait.h>
	#include <assert.h>

	int main(void)
	{
		for (int c = 0;;c++) {
			if ((c % 10000) == 0)
				printf("%d\n", c);

			if (fork())
				wait(NULL);
			else {
				assert(ptrace(PTRACE_ATTACH, 1, NULL,NULL) == 0);
				assert(wait(NULL) == 1);
				assert(ptrace(PTRACE_SINGLESTEP, 1, NULL, SIGWINCH) == 0);
				assert(wait(NULL) == 1);
				assert(ptrace(PTRACE_SINGLESTEP, 1, NULL, NULL) == 0);
				assert(wait(NULL) == 1);
				assert(ptrace(PTRACE_SINGLESTEP, 1, NULL, NULL) == 0);
				assert(wait(NULL) == 1);
				assert(ptrace(PTRACE_SINGLESTEP, 1, NULL, NULL) == 0);
				assert(wait(NULL) == 1);
				assert(ptrace(PTRACE_SINGLESTEP, 1, NULL, NULL) == 0);
				return 0;
			}
		}

		return 0;
	}

and it crashes the kernel WITH YOUR PATCH APPLIED. This proves that
the patch is racy even if the change in __ptrace_unlink() was correct.

Not sure this test-case will work on your machine, I ran it under qemu
with init=/bin/bash.

Chen, I am sorry, but I will not answer if you resend this patch again.

Oleg.

On 10/26, chen zhang wrote:
>
> I got below panic when doing fuzz test:
>
> Kernel panic - not syncing: Attempted to kill init! exitcode=0x00000005
> CPU: 2 PID: 1 Comm: systemd Kdump: loaded Not tainted 6.1.0-rc1 #1
> Hardware name: LENOVO 20L5A07XCD/20L5A07XCD, BIOS N24ET56W (1.31 ) 02/19/2020
> Call Trace:
> [  157.210356]  dump_stack_lvl+0x49/0x63
> [  157.210364]  dump_stack+0x10/0x16
> [  157.210368]  panic+0x10c/0x299
> [  157.210375]  do_exit.cold+0x15/0x15
> [  157.210381]  do_group_exit+0x35/0x90
> [  157.210386]  get_signal+0x910/0x960
> [  157.210390]  ? signal_wake_up_state+0x2e/0x40
> [  157.210396]  ? complete_signal+0xd0/0x2c0
> [  157.210402]  arch_do_signal_or_restart+0x37/0x7c0
> [  157.210408]  ? send_signal_locked+0xf5/0x140
> [  157.210416]  exit_to_user_mode_prepare+0x133/0x180
> [  157.210423]  irqentry_exit_to_user_mode+0x9/0x20
> [  157.210428]  noist_exc_debug+0xea/0x150
> [  157.210433]  asm_exc_debug+0x34/0x40
> [  157.210438] RIP: 0033:0x7fcf2a8e51c9
> [  157.210442] Code: ff ff 73 01 c3 48 8b 0d c5 7c 0c 00 f7 d8 64 89 01 48 83 c8 ff c3 66 2e 0f 1f 84 00 00 00 00 00 90 f3 0f 1e fa b8 ba 00 00 00 <0f> 05 c3 0f 1f 40 00 f3 0f 1e fa b8 ea 00 00 00 0f 05 48 3d 01 f0
> [  157.210446] RSP: 002b:00007ffd7dc44678 EFLAGS: 00000302
> [  157.210451] RAX: 00000000000000ba RBX: 000055f7c0363170 RCX: 000055f7c04d2820
> [  157.210454] RDX: 00000000ffffffff RSI: ffffffffffffffff RDI: 000055f7c0363170
> [  157.210457] RBP: 0000000000000001 R08: 0000000000000000 R09: 0000000000001dd0
> [  157.210460] R10: 00007ffd7ddc9090 R11: 000000000000d7da R12: 0000000000000001
> [  157.210463] R13: ffffffffffffffff R14: 000055f7bf3557c1 R15: 0000000000000000
>
> If a task attaches init task and is single stepping it, when this task
> exits, ptrace value will be cleaned. It causes SIGNAL_UNKILLABLE flag
> cleaned, and init task will lose the protection. Init task maybe be killed
> by SIGTRAP signal because of stepping enabled. So syscall tracing and
> stepping should be turned off for protecting init task before ptrace value
> is cleaned.
>
> Signed-off-by: chen zhang <chenzhang@kylinos.cn>
> ---
> change for v2: remove _TIF_SINGLESTEP because of some architecture has not defined _TIF_SINGLESTEP such as mips.
>
> change for v3:
> Thanks for your reply and your patience. Let us discuss if the patch is useful to avoid kernel panic. In my x86 machine,
> I tested v5.4.18 kernel version, v5.15.67 kernel version and v6.1.0-rc1 kernel version.
> My test C codes include:
>   r[3] = 1;
>   syscall(__NR_ptrace, 0x4206, r[3], 0, 0);
>   syscall(__NR_ptrace, 0x4207, r[3]);
>   syscall(__NR_ptrace, 9, r[3], 0, 0);
> I tested while(1) loop and ctrl-c operation, fork and call ptrace syscall, loop 100 times syscalls and so on. The kernel will be in panic.
> For example in 5.4 kernel, trap signal is sent by two pathes:
> the one is:
> 	force_sig_info_to_task.cold+0x71/0x76
> 	force_sig_fault+0x63/0x80
> 	send_sigtrap+0x45/0x50
> 	do_debug+0x170/0x210
> 	debug+0x3f/0x60
> 	debug+0x53/0x60
> the other one is:
> 	force_sig_info_to_task.cold+0x84/0x8e
> 	force_sig_fault+0x63/0x80
> 	user_single_step_report+0x49/0x50
> 	syscall_slow_exit_work+0x75/0x150
> 	do_syscall_64+0x156/0x190
> 	entry_SYSCALL_64_after_hwframe+0x44/0xa9
> I debugged the sigtrap sending and get_signal function. When the debugger exits, the first sigtrap
> is prevent by SIGNAL_UNKILLABLE flag in get_signal function. Without my patch, the second sigtrap will be sent,
> and kernel will be in panic.
> I added my patch into the kernel:
> +	if (unlikely(child->signal->flags & SIGNAL_UNKILLABLE) &&
> +	    unlikely(task_thread_info(child)->flags & _TIF_SINGLESTEP))
> +		user_disable_single_step(child);
> I test the kernel with my patch, the kernel will not be in panic when I run my test program or ctrl-c the test program.
> So I think my patch is efficient to avoid kernel panic. You said:
> - debugger does ptrace(PTRACE_SINGLESTEP), this wakes the tracee up
> - the tracee enters force_sig_info_to_task(SIGTRAP) after single step
> - debugger exits, __ptrace_unlink() clears ptrace/TIF_SINGLESTEP
> - force_sig_info_to_task() clears SIGNAL_UNKILLABLE, the traced init will be killed.
>
> But run kernel with my patch, I can not find SIGTRAP signal without SIGNAL_UNKILLABLE flag for init task in get_signal function,
> so the kernel can not be in panic. Please let me verify my patch, I write a simple test, test.c includes
>   r[3] = 1;
>   syscall(__NR_ptrace, 0x4206, r[3], 0, 0);  /* ptrace(PTRACE_SEIZE, 1, NULL, 0) */
>   syscall(__NR_ptrace, 0x4207, r[3]);		/* ptrace(PTRACE_INTERRUPT, 1) */
>   syscall(__NR_ptrace, 9, r[3], 0, 0);		/* ptrace(PTRACE_SINGLESTEP, 1, NULL, 0) */
>   syscall(__NR_ptrace, 9, r[3], 0, 0);		/* ptrace(PTRACE_SINGLESTEP, 1, NULL, 0) */
>   sleep(10000);
> When test is sleeping, I will ctrl-c to stop the test. Do you think the traced init will be killed by SIGTRAP and my patch is unuseful?
> For verify my patch, I add three debug in the kernel of 6.1.0-rc1:
> 1. kernel/ptrace.c
> printk("user_disable_single_step will be called in __ptrace_unlink, child is %s, parent is %s, cpu is %d\n",
> child->comm, child->parent->comm, smp_processor_id());
> 2. kernel/signal.c
> bool get_signal(struct ksignal *ksig) {
> 	...
> 	/* Trace actually delivered signals. */
> 	trace_signal_deliver(signr, &ksig->info, ka);
> 	/* chen zhang add */
> 	if (current->pid == 1 && signr == 5) {
> 		printk("current->siganl->flags is 0x%x,current->parent is %s, ptrace is %d, cpu is %d in get_signal\n",
> 			current->signal->flags, current->parent->comm, current->ptrace, smp_processor_id());
> 		if (unlikely(signal->flags & SIGNAL_UNKILLABLE) &&
> 				!sig_kernel_only(signr))
> 			printk("flages is SIGNAL_UNKILLABLE in get_signal\n");
> 		else
> 			printk("SIGNAL_UNKILLABLE is clear in get_signal\n");
>
>
> 	}
> 	/* chen zhang add end */
> 	if (!signr)
> 		break; /* will return 0 */
> 	...
>
> }
> 3. kernel/signal.c
> static int
> force_sig_info_to_task(struct kernel_siginfo *info, struct task_struct *t,
> 	enum sig_handler handler) {
> 	...
> 	/* chen zhang add */
> 	if (t->pid == 1 && sig == 5) {
> 		printk("init will send sigtrap in force_sig_info_to_task, ptrace is %d, parent is %s,"
> 			"regs eflags is 0x%lx, thread info flags is 0x%lx, cpu is %d\n",
> 			t->ptrace,t->parent->comm,task_pt_regs(t)->flags,
> 			task_thread_info(t)->flags,smp_processor_id());
> 	}
> 	/* chen zhang add end */
> 	if (action->sa.sa_handler == SIG_DFL &&
> 	    (!t->ptrace || (handler == HANDLER_EXIT))) {
> 	    	/* chen zhang add */
> 	    	printk("SIGNAL_UNKILLABLE will be clear in force_sig_info_to_task, pid is %d, sig is %d\n", t->pid, sig);
> 	    	/* chen zhang add end */
> 		t->signal->flags &= ~SIGNAL_UNKILLABLE;
> 	}
> 	ret = send_signal_locked(sig, info, t, PIDTYPE_PID);
> 	...
> }
> I installed the debug kernel with my patch and run strace ./test, dmesg:
> [  768.416269] init will send sigtrap in force_sig_info_to_task, ptrace is 65537, parent is test,regs eflags is 0x306, thread info flags is 0x1000010, cpu is 1
> [  768.416288] init will send sigtrap in force_sig_info_to_task, ptrace is 65537, parent is test,regs eflags is 0x306, thread info flags is 0x1000010, cpu is 1
> After ctrl-c
> [  780.963530] user_disable_single_step will be called in __ptrace_unlink, child is systemd, parent is swapper/0, cpu is 5
> [  780.963580] current->siganl->flags is 0x40,current->parent is swapper/0, ptrace is 0, cpu is 6 in get_signal
> [  780.963583] flages is SIGNAL_UNKILLABLE in get_signal
>
> Kernel is not in panic. I also use orignal test program, it autogenerated by syzkaller. And it use fork and while(1) loop.
> When it run, the orignal kernel of v6.1.0-rc1 without my patch must be appear panic immediately.
> Now test my kernel, ./err_orig, run two minutes, then ctrl+c stop it, tail of dmesg:
> [ 1993.688471] user_disable_single_step will be called in __ptrace_unlink, child is systemd, parent is swapper/0, cpu is 0
> [ 1993.688514] current->siganl->flags is 0x40,current->parent is swapper/0, ptrace is 0, cpu is 7 in get_signal
> [ 1993.688516] flages is SIGNAL_UNKILLABLE in get_signal
> [ 1993.724130] init will send sigtrap in force_sig_info_to_task, ptrace is 65537, parent is err_orig,regs eflags is 0x306, thread info flags is 0x1000010, cpu is 1
> [ 1993.724299] user_disable_single_step will be called in __ptrace_unlink, child is systemd, parent is swapper/0, cpu is 5
> [ 1993.724367] current->siganl->flags is 0x40,current->parent is swapper/0, ptrace is 0, cpu is 2 in get_signal
> [ 1993.724372] flages is SIGNAL_UNKILLABLE in get_signal
>
> It seemed running well and no kernel panic happened, SIGNAL_UNKILLABLE flag always protected the init task. My patch disabled
> hardware debug on time and avoid many SIGTRIP signals to be created and sent. So my patch is useful and it can avoid kernel
> panic. At last I expect and welcome you review and verify my patch on your x86 machine. You can also give me a test case that
> can cause kernel panic, I will test it on my kernel. Thanks again!
>
> ---
>  kernel/ptrace.c | 3 +++
>  1 file changed, 3 insertions(+)
>
> diff --git a/kernel/ptrace.c b/kernel/ptrace.c
> index 54482193e1ed..e7c41154b31e 100644
> --- a/kernel/ptrace.c
> +++ b/kernel/ptrace.c
> @@ -130,6 +130,9 @@ void __ptrace_unlink(struct task_struct *child)
>  	put_cred(old_cred);
>
>  	spin_lock(&child->sighand->siglock);
> +	if (unlikely(child->signal->flags & SIGNAL_UNKILLABLE) &&
> +	    unlikely(task_thread_info(child)->flags & _TIF_SINGLESTEP))
> +		user_disable_single_step(child);
>  	child->ptrace = 0;
>  	/*
>  	 * Clear all pending traps and TRAPPING.  TRAPPING should be
> --
> 2.25.1
>


^ permalink raw reply	[flat|nested] 2+ messages in thread

end of thread, other threads:[~2022-10-26 13:57 UTC | newest]

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2022-10-26  5:29 [PATCH v3] ptrace: disable single step in __ptrace_unlink for protecting init task chen zhang
2022-10-26 13:55 ` Oleg Nesterov

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